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Find the smallest number which leaves …

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Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively.
  • 13 answers
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<font size=12><font color=blue>sanket
<font size=20>Ayush
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Hardik Panwar 5 years, 8 months ago

28-8=20 & 32-12=20 So the reqd no will be 20 less than the L. C. M. of 28 and 32 . L. C. M. of 28 & 32 is = 224 Reqd smallest no =224-20 = 204.
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